Taskflow
2.7.0
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Taskflow provides template function that constructs a task to perform parallel reduction over a range of items.
The reduction task created by tf::Taskflow::reduce(B&& first, E&& last, T& result, O&& bop) performs parallel reduction over a range of elements specified by [beg, end)
using the binary operator bop
and stores the reduced result in result
. It represents the parallel execution of the following reduction loop:
At runtime, the reduction task spawns a subflow to perform parallel reduction. The reduced result is stored in result
that will be captured by reference in the reduction task. It is your responsibility to ensure result
remains alive during the parallel execution.
The order in which the binary operator is applied to pairs of elements is unspecified. In other words, the elements of the range may be grouped and rearranged in arbitrary order. The result and the argument types of the binary operator must be consistent with the input data type .
Similar to A0: Parallel Iterations, you may leverage std::reference_wrapper to enable stateful parameter passing between tasks for expressing end-to-end parallelism.
In the above example, when init
finishes, vec
has been initialized to 10 elements with first
pointing to the first element and last
pointing to the next of the last element (i.e., end of the range). These changes are visible to the execution context of the reduction task.
It is common to transform each element into a new data type and then perform reduction on the transformed elements. Taskflow provides a method, tf::Taskflow::transform_reduce(B&& first, E&& last, T& result, BOP&& bop, UOP&& uop), that applies uop
to transform each element in the specified range and then perform parallel reduction over result
and transformed elements. It represents the parallel execution of the following reduction loop:
The example below transforms each digit in a string to an integer number and then sums up all integers in parallel.
The order in which we apply the binary operator on the transformed elements is unspecified. It is possible that the binary operator will take r-value in both arguments, for example, bop(uop(*itr1), uop(*itr2))
, due to the transformed temporaries. When data passing is expensive, you may define the result type T
to be move-constructible.